If (h,k) is the image of the point (3,4) with respect to the line 2x - 3y -5 = 0 and (l,m) is the foot of the perpendicular from (h,k) on the line 3x + 2y + 12 = 0, then lh + mk + 1 = 2x - 3y - 5 = 0.
5
\(\frac{-1}{34}\)
\(\frac{-3}{34}\)
-3
The correct option is: (A) 5
If sin y = sin 3t and x = sin t, then \(\frac{dy}{dx}\) =
If A is a square matrix of order 3, then |Adj(Adj A2)| =
Match the following List -I (Complex) List II (Spin only Magnetic Moment)
List -I (Complex) | List II (Spin only Magnetic Moment) | ||
A) | [CoF6]3- | I) | 0 |
B) | [Co(C2O4)3]3- | II) | √24 |
C) | [FeF6]3+ | III) | √8 |
D) | [Mn(CN)6]3- | IV) | √35 |
V) | √15 |
the correct answer is:
If a line ax + 2y = k forms a triangle of area 3 sq.units with the coordinate axis and is perpendicular to the line 2x - 3y + 7 = 0, then the product of all the possible values of k is
If i=√-1 then
\[Arg\left[ \frac{(1+i)^{2025}}{1+i^{2022}} \right] =\]