Question

If force of friction of material is \(1 / 4^{\text{th}}\) of the force normal to the surface of contact, then coefficient of friction will be equal to:

• A. 0.25
• B. 0.50
• C. 0.75
• D. 4.00

Hint:

Coefficient of friction is always a dimensionless number.
It ranges from 0 to 1 for most materials.
\(\mu = \tan \theta\), where \(\theta\) is the angle of friction.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Coefficient of friction (\(\mu\)) is the ratio of frictional force to normal force.
It is a measure of the resistance to sliding between two surfaces.

Step 2: Key Formula or Approach:
\(\mu = \frac{F}{N}\)
Where F is the force of friction and N is the normal force.

Step 3: Detailed Explanation:
Given that the force of friction is \(1/4^{\text{th}}\) of the normal force.
So, \(F = \frac{1}{4} \times N\).
Therefore, \(\mu = \frac{F}{N} = \frac{\frac{1}{4} \times N}{N} = \frac{1}{4} = 0.25\).

Step 4: Final Answer:
The coefficient of friction is 0.
Hence, the correct option is (A).