Question:

If \(f:[a,b]\to R\) is Riemann integrable, then

Show Hint

The absolute value of an integral is always less than or equal to the integral of the absolute value.
  • \(\left|\displaystyle\int_a^b f(x)\,dx\right|\leq \displaystyle\int_a^b |f(x)|\,dx\)
  • \(\displaystyle\int_a^b |f(x)|\,dx\leq \left|\displaystyle\int_a^b f(x)\,dx\right|\)
  • \(\displaystyle\int_a^b |f(x)|\,dx=\left|\displaystyle\int_a^b f(x)\,dx\right|\)
  • \(\left|\displaystyle\int_a^b f(x)\,dx\right|=\displaystyle\int_a^b f(x)\,dx\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Concept:
A standard inequality for integrals is \[ \left|\int_a^b f(x)\,dx\right|\leq \int_a^b |f(x)|\,dx \] This is the integral form of the triangle inequality.

Step 1: Use pointwise inequality.
For every \(x\), \[ -|f(x)|\leq f(x)\leq |f(x)| \]

Step 2: Integrate throughout.
\[ -\int_a^b |f(x)|\,dx \leq \int_a^b f(x)\,dx \leq \int_a^b |f(x)|\,dx \] This implies \[ \left|\int_a^b f(x)\,dx\right| \leq \int_a^b |f(x)|\,dx \]

Step 3: Final answer.
\[ \boxed{\left|\int_a^b f(x)\,dx\right|\leq \int_a^b |f(x)|\,dx} \]
Was this answer helpful?
0
0