Question:

If crosses were made with 8 parents in the diallel mating system (excluding reciprocals), what would be total numbers of F$_1$'s?

Show Hint

Diallel mating design:
- Excluding reciprocals: $\frac{n(n-1)}{2}$.
- Including reciprocals: n(n-1).
- Used to estimate combining ability.
  • 56
  • 64
  • 32
  • 28
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Question:
This question tests knowledge of diallel mating design.

Step 2: Key Formula or Approach:

In a diallel cross (excluding reciprocals), the number of F$_1$ combinations is given by:
\[ \frac{n(n-1)}{2} \] where n is the number of parents.

Step 3: Detailed Explanation:

Given: n = 8 parents.
Number of F$_1$ crosses = $\frac{8 \times 7}{2} = 28$.
Thus, there are 28 F$_1$ combinations.
56 (A): This is for complete diallel including reciprocals.
64 (B): Not correct.
32 (C): Not correct.
Final Answer:
Thus, the total number of F$_1$'s is 28, which corresponds to option (D).
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