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How many ten-digit numbers can be formed using all the digits of 2435753228 such that odd digits appear only in even places?
How many ten-digit numbers can be formed using all the digits of 2435753228 such that odd digits appear only in even places?
Updated On: Jul 30, 2024
- 2! 3! 5!
- $(5!)^2$
- $\frac{(5!)^2}{3!}$
- $\frac{(5!)^2}{3!(2!)^2}$
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The Correct Option is D
Solution and Explanation
The Correct option is (D):$\frac{(5!)^2}{3!(2!)^2}$
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