Question

Given below are two statements :
Statement I : If the Brewster's angle for the light propagating from air to glass is $\theta_{ B }$, then the Brewster's angle for the light propagating from glass to air is $\frac{\pi}{2}-\theta_m$
Statement II : The Brewster's angle for the light propagating from glass to air is $\tan ^{-1}\left(\mu_{ g }\right)$ where $\mu_{ g }$ is the refractive index of glass
In the light of the above statements choose the correct answer from the options given below:

• A. Both Statement I and Statement II are true
• B. Both Statement I and Statement II are false
• C. Statement I is true but Statement II is false
• D. Statement I is false but Statement II is true

Answer 1

The Correct Option is C

${\mu }_a\sin i_1={\mu }_g\sin \left(90-i_1\right)$
$\tan i_1=\frac{{\mu }_g}{{\mu }_a}$
When going from glass to air
$\tan i_2=\frac{{\mu }_a}{{\mu }_g}=\cot i_1$
Hence
$i_2=\frac{\pi }{2}-i_1$