Question:

\( \frac{dy}{dx} = F(x, y) \) will be a homogeneous differential equation for which of the following functions ? 
(i) \( F(x, y) = 3x + 2y \) 
(ii) \(F(x, y) = \sin \frac{y}{x} + \log y - \log x\)
(iii) \( F(x, y) = e^{y/x} + 1 \) 
(iv) \( F(x, y) = \sqrt{x^2 + y^2} - y \)}

Show Hint

A quick shortcut: if every term in the expression has the same combined power of \( x \) and \( y \), and those powers cancel out to zero, the function is homogeneous. Look for functions that only contain terms like \( y/x \), \( \sin(y/x) \), \( e^{y/x} \), or \( \log(y/x) \).
Updated On: Sep 11, 2026
  • (i) and (ii)
  • (i), (ii) and (iii)
  • (ii), (iii) and (iv)
  • (ii) and (iii)
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The Correct Option is D

Solution and Explanation

Concept:
• A differential equation \( \frac{dy}{dx} = F(x, y) \) is homogeneous if \( F(x, y) \) is a homogeneous function of degree zero.
• A function is homogeneous of degree zero if \( F(\lambda x, \lambda y) = F(x, y) \) for any non-zero scalar \( \lambda \).
• This effectively means \( F(x, y) \) can be expressed solely as a function of the ratio \( \frac{y}{x} \).

Step 1:
Test function (i)
\( F(x, y) = 3x + 2y \) \[ F(\lambda x, \lambda y) = 3(\lambda x) + 2(\lambda y) = \lambda(3x + 2y) \neq F(x, y) \] This is degree 1, not homogeneous of degree 0.

Step 2:
Test function (ii)
\( F(x, y) = \sin \frac{y}{x} + \log y - \log x = \sin \frac{y}{x} + \log \left(\frac{y}{x}\right) \) \[ F(\lambda x, \lambda y) = \sin \left(\frac{\lambda y}{\lambda x}\right) + \log \left(\frac{\lambda y}{\lambda x}\right) = \sin \frac{y}{x} + \log \frac{y}{x} = F(x, y) \] This is degree 0, so it is a homogeneous differential equation.

Step 3:
Test function (iii)
\( F(x, y) = e^{y/x} + 1 \) \[ F(\lambda x, \lambda y) = e^{\lambda y / \lambda x} + 1 = e^{y/x} + 1 = F(x, y) \] This is degree 0, so it is a homogeneous differential equation.

Step 4:
Test function (iv)
\( F(x, y) = \sqrt{x^2 + y^2} - y \) \[ F(\lambda x, \lambda y) = \sqrt{(\lambda x)^2 + (\lambda y)^2} - \lambda y = \lambda(\sqrt{x^2 + y^2} - y) \neq F(x, y) \] This is degree 1, not homogeneous of degree 0.
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