Concept:
Breakaway and break-in points on a root locus are obtained from
\[
\frac{dK}{ds}=0.
\]
Step 1: Find the characteristic equation.
\[
1+\frac{K(s+a)}{(s+b)^2}=0
\]
which gives
\[
K=-\frac{(s+b)^2}{s+a}.
\]
Step 2: Differentiate with respect to \(s\).
\[
\frac{dK}{ds}=0.
\]
Applying quotient rule,
\[
(s+b)\Big[(s+a)-2(s+b)\Big]=0.
\]
After simplification, the break points are obtained as
\[
s=-b\pm\sqrt{b^2-ab}.
\]
Step 3: Final result.
\[
\boxed{s=-b\pm\sqrt{b^2-ab}}
\]
Hence,
\[
\boxed{\text{Correct Option (D)}}
\]
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