Question:

For the parabola $y^2 + 6\,y - 2x = - 5$ I. the vertex is $( - 2,-3)$ II. the directrix is $y + 3 = 0$ Which of the following is correct?

Updated On: Aug 15, 2024
  • Both I and II are correct
  • I is true, II is false
  • Both I and II are false
  • I is false, II is true
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The Correct Option is B

Solution and Explanation

We have,
$y^{2}+6 \,y-2\, x=-5$
$\Rightarrow y^{2}+6\, y=2\, x-5$
$\Rightarrow y^{2}+6\, y+9=2 x-5+9$
$\Rightarrow (y+3)^{2}=2\, x+4$
$\Rightarrow (y+3)^{2}=2(x+2)$
$\therefore 4 a=2 \Rightarrow a=\frac{1}{2}$
Vertex $=(-2,-3)$
Equations of directrix
$x+2=-\frac{1}{2}$
$\Rightarrow x+\frac{5}{2}=0$
$\Rightarrow 2 \,x+5=0$
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Concepts Used:

Parabola

Parabola is defined as the locus of points equidistant from a fixed point (called focus) and a fixed-line (called directrix).

Parabola


 

 

 

 

 

 

 

 

 

Standard Equation of a Parabola

For horizontal parabola

  • Let us consider
  • Origin (0,0) as the parabola's vertex A,
  1. Two equidistant points S(a,0) as focus, and Z(- a,0) as a directrix point,
  2. P(x,y) as the moving point.
  • Let us now draw SZ perpendicular from S to the directrix. Then, SZ will be the axis of the parabola.
  • The centre point of SZ i.e. A will now lie on the locus of P, i.e. AS = AZ.
  • The x-axis will be along the line AS, and the y-axis will be along the perpendicular to AS at A, as in the figure.
  • By definition PM = PS

=> MP2 = PS2 

  • So, (a + x)2 = (x - a)2 + y2.
  • Hence, we can get the equation of horizontal parabola as y2 = 4ax.

For vertical parabola

  • Let us consider
  • Origin (0,0) as the parabola's vertex A
  1. Two equidistant points, S(0,b) as focus and Z(0, -b) as a directrix point
  2. P(x,y) as any moving point
  • Let us now draw a perpendicular SZ from S to the directrix.
  • Then SZ will be the axis of the parabola. Now, the midpoint of SZ i.e. A, will lie on P’s locus i.e. AS=AZ.
  • The y-axis will be along the line AS, and the x-axis will be perpendicular to AS at A, as shown in the figure.
  • By definition PM = PS

=> MP2 = PS2

So, (b + y)2 = (y - b)2 + x2

  • As a result, the vertical parabola equation is x2= 4by.