Step 1: Identify total Sundays in a leap year. A leap year has 366 days, which means 52 complete weeks + 2 extra days.
Step 2: Determine favorable cases. The extra 2 days can be: \begin{itemize} \item - (Sunday, Monday) \item - (Monday, Tuesday) \item - (Tuesday, Wednesday) \item - (Wednesday, Thursday) \item - (Thursday, Friday) \item - (Friday, Saturday) \item - (Saturday, Sunday) \end{itemize} In 2 out of 7 cases, Sunday is included.
Step 3: Compute probability. \[ P(\text{53 Sundays}) = \frac{2}{7} \]
There are 10 black and 5 white balls in a bag. Two balls are taken out, one after another, and the first ball is not placed back before the second is taken out. Assume that the drawing of each ball from the bag is equally likely. What is the probability that both the balls drawn are black?
The probabilities of solving a question by \( A \) and \( B \) independently are \( \frac{1}{2} \) and \( \frac{1}{3} \) respectively. If both of them try to solve it independently, find the probability that:
The given events \( A \) and \( B \) are such that \( P(A) = \frac{1}{4} \), \( P(B) = \frac{1}{2} \), and \( P(A \cap B) = \frac{1}{8} \); then find \( P(A' \cap B') \).