Step 1: Identify the operation between consecutive terms.
\[
2\times3-1=5
\]
\[
5\times3-1=14
\]
\[
14\times3-1=41
\]
\[
41\times3-1=122
\]
Thus the rule is:
\[
a_{n+1}=3a_n-1
\]
Step 2: Apply the rule to the last term.
\[
122\times3-1=366-1=365
\]
Therefore, the next term is
{365}