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Find the distance between two consecutive nodes if a string has tension 0.25 N, mass per unit length is 1 mg/m and frequency is 250 Hz.
Find the distance between two consecutive nodes if a string has tension 0.25 N, mass per unit length is 1 mg/m and frequency is 250 Hz.
Updated On: Jun 2, 2024
- 2 m
- 1 m
- 3 m
- 1.5 M
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The Correct Option is B
Solution and Explanation
The speed of transverse wave on the string will
be, \(v=\sqrt{\frac{T}{m}}\)
\(v=\sqrt{\frac{0.25}{1\times10^{-6}}}\)
\(v = 500 \,m/sec\)
and
\(v = f \lambda\)
So, \(\lambda=\frac{500}{250}\)
\(\lambda=2\) m
Distance between two consecutive nodes is given by,
\(=\frac{\lambda}{2}=1\) m
So, the correct option is (B) : 1 m.
be, \(v=\sqrt{\frac{T}{m}}\)
\(v=\sqrt{\frac{0.25}{1\times10^{-6}}}\)
\(v = 500 \,m/sec\)
and
\(v = f \lambda\)
So, \(\lambda=\frac{500}{250}\)
\(\lambda=2\) m
Distance between two consecutive nodes is given by,
\(=\frac{\lambda}{2}=1\) m
So, the correct option is (B) : 1 m.
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