E. Coli about to replicate was placed in a medium containing radio active thymidine for five minutes. Then it was made to replicate in a normal medium. Which of the following observation shall be correct
- Both the strands of DNA will be radio active
- One strand radio active
- Each strand half radio active
- None is radio active
The Correct Option is B
Solution and Explanation
When E. coli is exposed to radioactive thymidine for a short period (5 minutes in this case), only one strand of the DNA will become radioactive. This is because DNA replication is a semi-conservative process. So, the correct observation is (B): One strand radioactive
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Concepts Used:
DNA Replication
The process by which the genome’s DNA is copied in cells is called DNA Replication. It must first copy (or replicate) its entire genome before cell division so that each resulting daughter cell ends up with its own complete genome.
It is the natural cycle of creating two indistinguishable imitations of DNA from one unique DNA molecule. DNA replication happens to take all things together living creatures going about as the most core part for organic legacy. This is important for cell division during the development and fixation of harmed tissues, while it likewise guarantees that every one of the new cells gets its duplicate of the DNA. The phone has the unmistakable property of division, which makes replication of DNA fundamental.
The parental DNA stays together, and the recently shaped daughter strands are together in conservative replication. The semi-conservative strategy recommends that every one of the two parental DNA strands goes about as a format for new DNA to be integrated; after that each two-fold abandoned DNA incorporates one "old" strand (parental) and one "new" strand.
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