Question

Determine the rate of application of a tractor operated sprayer having 9 m swath. A chemical is sprayed at 30 liters per minute with forward speed of 4 km.h\(^{-1}\).

• A. 500 l ha\(^{-1}\)
• B. 1000 l ha\(^{-1}\)
• C. 1500 l ha\(^{-1}\)
• D. 1800 l ha\(^{-1}\)

Hint:

Remember:
1 km/h = 1000 m/h.
1 hectare = 10000 m\(^2\).
Always convert units to get the correct answer.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
We need to find the application rate in liters per hectare.
We have the swath width, flow rate, and speed.

Step 2: Key Formula or Approach:
Area covered per hour = Swath width \(\times\) Speed.
Volume sprayed per hour = Flow rate \(\times\) 60.
Application rate = Volume sprayed per hour Area covered per hour.

Step 3: Detailed Explanation:
Swath width = 9 m.
Speed = 4 km/h = 4000 m/h.
Area covered per hour = 9 \(\times\) 4000 = 36000 m\(^2\)/h.
Flow rate = 30 liters/min = 30 \(\times\) 60 = 1800 liters/h.
Application rate = 1800 36000 = 0.05 liters/m\(^2\).
To convert to liters per hectare: 1 ha = 10000 m\(^2\).
Application rate = 0.05 \(\times\) 10000 = 500 liters/ha.

Step 4: Final Answer:
The rate of application is 500 l ha\(^{-1}\).
Hence, the correct option is (A).