Question

Certain neutron stars are believed to be rotating at about 1 rev /s. If such a star has a radius of 20 km, the acceleration of an object on the equator of the star will be

• A. $ 20\times {{10}^{8}}m/{{s}^{2}} $
• B. $ 8\times {{10}^{s}}m/{{s}^{2}} $
• C. $ 120\times {{10}^{s}}m/{{s}^{2}} $
• D. $ 4\times {{10}^{8}}m/{{s}^{2}} $

Answer 1

The Correct Option is B

$ a={{\omega }^{2}}r=4{{\pi }^{2}}{{v}^{2}}r $ $ =4\times {{\pi }^{2}}\times {{1}^{2}}\times 20\times {{10}^{3}} $ $ \therefore $ $ a=8\times {{10}^{5}}m/{{s}^{2}} $