Question:

Box A has 10 green balls and 8 black balls. Box B has 9 green balls and 5 black balls. What is the probability that one ball drawn from each box is green?

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For independent events, multiply probabilities: \(P(A \cap B) = P(A) \times P(B)\).
Updated On: Oct 3, 2025
  • \(\tfrac{5}{14}\)
  • \(\tfrac{10}{49}\)
  • \(\tfrac{5}{9}\)
  • \(\tfrac{9}{14}\)
  • \(\tfrac{19}{252}\)
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The Correct Option is C

Solution and Explanation

Step 1: Probability from Box A.
\[ P(\text{green from A}) = \frac{10}{18} = \frac{5}{9}. \] Step 2: Probability from Box B.
\[ P(\text{green from B}) = \frac{9}{14}. \] Step 3: Multiply.
\[ \frac{5}{9} \times \frac{9}{14} = \frac{5}{14}. \] So the correct probability is \(\tfrac{5}{14}\).
Final Answer: \[ \boxed{\tfrac{5}{14}} \]
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