Step 1: The area of the circle is equal to the area of the square. The area of the square is given by: \[ \text{Area of square} = \text{side}^2 = 10^2 = 100 \, \text{cm}^2. \] Step 2: The area of the circle is \( \pi r^2 \), where \( r \) is the radius. Thus, we can equate the area of the circle to the area of the square: \[ \pi r^2 = 100 \] Solving for \( r^2 \): \[ r^2 = \frac{100}{\pi} \] Taking the square root of both sides: \[ r = \sqrt{\frac{100}{\pi}} \] Step 3: The circumference of the circle is given by \( 2\pi r \). Substituting the value of \( r \): \[ \text{Circumference} = 2\pi \times \sqrt{\frac{100}{\pi}} = 20\sqrt{\pi} \, \text{cm}. \]
The center of a circle $ C $ is at the center of the ellipse $ E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 $, where $ a>b $. Let $ C $ pass through the foci $ F_1 $ and $ F_2 $ of $ E $ such that the circle $ C $ and the ellipse $ E $ intersect at four points. Let $ P $ be one of these four points. If the area of the triangle $ PF_1F_2 $ is 30 and the length of the major axis of $ E $ is 17, then the distance between the foci of $ E $ is: