Question

An incompressible fluid is flowing through a vertical pipe (height h and crosssectional area 𝐴_𝑜). A thin mesh, having n circular holes of area 𝐴_ℎ is fixed at the bottom end of the pipe. The speed of the fluid entering the top-end of the pipe is 𝑣_𝑜. The volume flow rate from an individual hole of the mesh is given by:
(g is the acceleration due to gravity)

• A. \(\frac{A_0}{n}\sqrt{v^2_o+2gh}\)
• B. \(\frac{A_0}{n}\sqrt{v^2_o+gh}\)
• C. \(n(A_O-A_h)\sqrt{v^2_o+2gh}\)
• D. \(n(A_O-A_h)\sqrt{v^2_o+gh_o}\)

Answer 1

The Correct Option is A

The correct option is (A): \(\frac{A_0}{n}\sqrt{v^2_o+2gh}\)