Question:
An equilateral triangle is inscribed in the circle x²+y²=a² with one of the vertices at (a,0). What is the equation of the side opposite to this vertex?
An equilateral triangle is inscribed in the circle x²+y²=a² with one of the vertices at (a,0). What is the equation of the side opposite to this vertex?
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For an equilateral triangle in a circle, opposite side lies at distance a/2 from the center.
Updated On: Mar 20, 2026
- \(2x+a=0\)
- \(x+a=0\)
- \(3x-2a=0\)
- 3x-2a=0
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The Correct Option is A
Solution and Explanation
In an equilateral triangle inscribed in a circle of radius a, the opposite side to vertex (a,0) is a vertical line at
x=-(a)/(2).
Hence the equation is 2x+a=0.
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