After striking the floor a certain ball rebounds (4)/(5)th of its height from which it has fallen. The total distance that the ball travels before coming to rest if it is gently released from a height of 120m is
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For rebound problems:
Total distance=h+2h((r)/(1-r))
Initial fall distance =120.
Rebound ratio r=(4)/(5).
Total distance:
S = h + 2h(r+r²+r³+⋯)
S = 120 + 2(120)(((4)/(5))/(1-(4)/(5)))
=120+2(120)(4)=120+960=1080