Question:

According to Stefan-Boltzmann law, the radiant energy emitted by a black body is proportional to:

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Logic Tip: Radiation is incredibly sensitive to temperature. If you double the absolute temperature of an object, the heat it radiates doesn't just double—it increases by a factor of 16 ($2^4$)!
  • Absolute temperature
  • Square of absolute temperature
  • Cube of absolute temperature
  • Fourth power of absolute temperature
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The Correct Option is D

Solution and Explanation

Concept:
Thermal radiation is the emission of electromagnetic waves from all matter that has a temperature greater than absolute zero. The Stefan-Boltzmann law quantifies the total maximum thermal energy a perfect emitter (a black body) radiates.

Step 1:
The Stefan-Boltzmann law is mathematically expressed as $E = \sigma \cdot T^4$.

Step 2:
In this equation, '$E$' represents the total radiant heat energy emitted per unit surface area, and '$\sigma$' is the Stefan-Boltzmann constant (a fixed numerical value).

Step 3:
The variable '$T$' represents the absolute temperature of the black body's surface, measured in Kelvin.

Step 4:
The equation explicitly dictates that the emitted energy ($E$) scales with the temperature ($T$) raised to the power of 4.

Step 5:
Therefore, the radiant energy is directly proportional to the fourth power of the absolute temperature.
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