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A uniform heavy rod of mass \(20\) kg, cross sectional area \(0.4\) \(m^2\) and length \(20\) \(m\) is hanging from a fixed support. Neglecting the lateral contraction, the elongation in the rod due to its own weight is \(x × 10^{–9}\) \(m\). The value of \(x\) is _____(Given Young’s modulus \(Y = 2 × 10^{11} Nm^{–2}\)and g = \(10\; ms^{–2})\)
A uniform heavy rod of mass \(20\) kg, cross sectional area \(0.4\) \(m^2\) and length \(20\) \(m\) is hanging from a fixed support. Neglecting the lateral contraction, the elongation in the rod due to its own weight is \(x × 10^{–9}\) \(m\). The value of \(x\) is _____(Given Young’s modulus \(Y = 2 × 10^{11} Nm^{–2}\)and g = \(10\; ms^{–2})\)
Updated On: Oct 18, 2024
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Correct Answer: 25
Solution and Explanation
\(\frac{\frac{F}{A}}{\frac{ΔL}{L}} = Y\)
\(ΔL = \frac{FL}{AY }\)
= \(\frac{TavgL}{AY} = \frac{MgL}{2AY}\)
= \(\frac{20 \times 10 \times 20}{2 \times .4 \times 2 \times 10^{11}}\)
=\(\frac{ 4 \times 10. \times 10^{-11}}{4 \times 0.4}\)
= \(2.5 \times 10^{-8}\)
=\( 25 \times 10^{-9}\)
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Concepts Used:
Elastic and Inelastic Collisions
Elastic Collision:
According to elastic collision, the kinetic energy of the system will remain constant which means there will be no change in the kinetic energy of the system before and after the collision. It also goes along with the conservation of momentum.
Examples of Elastic Collision
- While playing billiards, balls hit each other.
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Inelastic Collision:
According to inelastic collision, the kinetic energy of the system is not conserved, unlike inelastic collision. The kinetic energy is lost as it gets debauched in other forms of energy like heat, sound, etc, or is absorbed by the body. But they go after the conservation of momentum, like an elastic collision.
Examples of Inelastic Collision
- When the ball is dropped on the ground, it fails to reach the height it was dropped from.
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