Question:

A stone is dropped from a certain height which can reach the ground in $5\,s$. If the stone is stopped after $3\, s$ of its fall and then allowed to fall again, then the time taken by the stone to reach the ground for die remaining distance is

Updated On: Jul 28, 2023
  • 2 s
  • 3 s
  • 4 s
  • None of these
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The Correct Option is C

Solution and Explanation

From, \(s=ut+\frac{1}{2}at^{2}\) Distance covered in \(5s\) \(s=0+\frac{1}{2}\times 10\times 5^{2}=125\,m\) Distance covered in \(3\,s\) \(s=0+\frac{1}{2}\times 10\times 3^{2}=45\,m\) Distance

 to be covered \(125-45=80\,m\) From, \(s=ut+\frac{1}{2}at^{2}\) \(80=0+\frac{1}{2}\times 10\,t^{2}\) \(t^{2}=\frac{80}{5}=16\) \(t=4\,s\)

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Concepts Used:

Newtons Laws of Motion

Newton’s First Law of Motion:

Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion:

Newton’s 2nd law states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.

Mathematically, we express the second law of motion as follows:

Newton’s Third Law of Motion:

Newton’s 3rd law states that there is an equal and opposite reaction for every action.