Question:

A proton moves with a velocity of 5 x 106 j m/s, through the uniform electric field E = 4 x 106 (2i + 0.2j + 0.1k) Vm-1and the uniform magnetic field B = 0.2( i + 0.2 j + k) T. The approximate net force acting on the proton is

Updated On: Aug 23, 2024
  • .2 x 10-13 N
  • 5 x 10-13 N
  • 2.0 x 10-13 N
  • 25 x 10-13 N
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The Correct Option is B

Solution and Explanation

The correct answer is (B) : 5 x 10-13 N
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