Question:

A player caught a cricket ball of mass 150 g moving at a speed of 20 m/s. If the catching process is completed in 0.1 s, the magnitude of force exerted by the ball on the hand of the player is:

Updated On: Nov 24, 2024
  • 150 N
  • 3 N
  • 30 N
  • 300 N
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The Correct Option is C

Solution and Explanation

The force exerted is:

\[ F = \frac{\Delta P}{\Delta t}. \]

Here:
\[ \Delta P = m \cdot v - 0 = 150 \times 10^{-3} \cdot 20 \, \text{kg m/s}, \]
\[ F = \frac{150 \times 10^{-3} \cdot 20}{0.1}. \]

\[ F = 30 \, \text{N}. \]

Final Answer: 30 N.

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