Question

A person invested some amount at the rate of 12\(\%\) simple interest and a certain amount at the rate of 10\(\%\) simple interest. He received yearly interest of Rs 130. But if he had interchanged the amounts invested, he would have received Rs 4 more as interest. How much did he invest at 12\(\%\) simple interest ?

• A. Rs 700
• B. Rs 500
• C. Rs 800
• D. Rs 400

Answer 1

The Correct Option is B

Let amount invested at 12% be x and amount invested at
10% be y.
According to question
130 = \(\frac{x × 12 × 1 }{100}\) + \(\frac{y × 10 × 1}{100}\)
\(⇒\)13000=12\(x\) + 10y  ……..(i)
And 134 = \(\frac{x × 10 × 1 }{100}\) + \(\frac{y × 12 × 1}{100}\)
\(⇒\)13400=10\(x\) + 12y  ……..(ii)
From equations (i) and (ii)
\(x\)=500
So the correct option is (B).