Question:

A particle of mass π‘š is under the influence of the gravitational field of a body of mass 𝑀 (≫ π‘š). The particle is moving in a circular orbit of radius \(π‘Ÿ_0\) with time period \(𝑇_0\) around the mass 𝑀. Then, the particle is subjected to an additional central force, corresponding to the potential energy 𝑉c(π‘Ÿ) = π‘šπ›Ό/π‘Ÿ 3 , where 𝛼 is a positive constant of suitable dimensions and π‘Ÿ is the distance from the center of the orbit. If the particle moves in the same circular orbit of radius\( π‘Ÿ_0\) in the combined gravitational potential due to 𝑀 and 𝑉c(π‘Ÿ), but with a new time period \(𝑇_1\), then\( (𝑇_1^2  βˆ’ 𝑇_0^ 2 )/𝑇_1^ 2\) is given by [𝐺 is the gravitational constant.]

Updated On: Oct 26, 2024
  • \(\frac{3\alpha}{ πΊπ‘€π‘Ÿ_0^2}\)
  • \(\frac{\alpha}{ 2πΊπ‘€π‘Ÿ_0^2}\)
  • \(\frac{\alpha}{ πΊπ‘€π‘Ÿ_0^2}\)
  • \(\frac{2\alpha}{πΊπ‘€π‘Ÿ_0^2}\)
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The Correct Option is A

Solution and Explanation

The correct option is (A):\(\frac{3\alpha}{ πΊπ‘€π‘Ÿ_0^2}\)
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