Question:
A man weighing 50 kg is in a lift moving down with an acceleration of $2.8 m s^{-2}$. The force exerted by the floor on him is:
A man weighing 50 kg is in a lift moving down with an acceleration of $2.8 m s^{-2}$. The force exerted by the floor on him is:
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Lift moving down $\rightarrow$ Apparent weight decreases.
Updated On: Jun 10, 2026
- 480 N
- 240 N
- 120 N
- 350 N
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Apparent weight in a lift moving down: $N = m(g - a)$.
Step 2: Analysis
$m = 50 kg$, $a = 2.8 m/s^2$, $g \approx 9.8 m/s^2$. $N = 50 \cdot (9.8 - 2.8) = 50 \cdot 7 = 350 N$.
Step 3: Conclusion
The force exerted by the floor is 350 N.
Final Answer: (D)
Apparent weight in a lift moving down: $N = m(g - a)$.
Step 2: Analysis
$m = 50 kg$, $a = 2.8 m/s^2$, $g \approx 9.8 m/s^2$. $N = 50 \cdot (9.8 - 2.8) = 50 \cdot 7 = 350 N$.
Step 3: Conclusion
The force exerted by the floor is 350 N.
Final Answer: (D)
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