The speed of a man went to a place =\(60km/h\)
The speed of a man returning to the same place =\(30km/h\)
\(Distance = Speed \times Time\)
\(Total Distance = Average Speed \times Total Time\)
Let us consider the Distance as D Total distance covered by the Man =\(D+D = 2D\)
\(Speed1= 60 km/hr\)
\(Speed2 = 30 km/hr\)
\(Time1=\frac{D}{60}\)
\(Time2 = \frac{D}{30}\)
\(Total Time = \frac{D}{60} + \frac{D}{30} = \frac{D}{20}\)
\(Average Speed = \frac{2D \times 20}{D}\)
\(Average Speed = 40km/hr\)
The correct answer is (A): 40 km/hr