Step 1: Equation for acceleration The acceleration of the system is given by:
\[ a_{\text{sys}} = \frac{(m_2 - m_1)}{m_1 + m_2} \cdot g. \]
Substitute \(a_{\text{sys}} = \frac{g}{8}\):
\[ \frac{(m_2 - m_1)}{m_1 + m_2} \cdot g = \frac{g}{8}. \]
Cancel \(g\) from both sides:
\[ \frac{m_2 - m_1}{m_1 + m_2} = \frac{1}{8}. \]
Step 2: Solve for \(\frac{m_2}{m_1}\) Rearrange the equation:
\[ 8(m_2 - m_1) = m_1 + m_2. \]
Simplify:
\[ 8m_2 - 8m_1 = m_1 + m_2. \]
Combine like terms:
\[ 8m_2 - m_2 = 8m_1 + m_1. \]
\[ 7m_2 = 9m_1. \]
Take the ratio:
\[ \frac{m_2}{m_1} = \frac{9}{7}. \]
Final Answer: \(\frac{m_2}{m_1} = 9 : 7\).
A horizontal force is exerted on a 20 kg box to slide it up on an inclined plane with an angle of 30°. The frictional force retarding the motion is 80 N. If the box moves with a constant speed, then the magnitude of the force is:(Take g=10 ms-2)
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: