Question:

A light ray is incident on a glass slab of thickness \(4\sqrt{3}\) cm and refractive index \(\sqrt{2}\). The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of the ray after passing through the glass slab is _____ cm.
(Given \(\sin 15^\circ = 0.25\))

Updated On: Nov 24, 2024
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Correct Answer: 2

Solution and Explanation

1. Calculate Total Mass of Reactants (\(m_r\)):
\[ m_r = 235.0439 \, \text{u}. \] 
2. Calculate Total Mass of Products (\(m_p\)): 
\[ m_p = 139.9054 + 93.9063 + 1.0086 = 234.8203 \, \text{u}. \] 
3. Calculate Disintegration Energy (\(Q\)): 
The disintegration energy \(Q\) is given by: 
\[ Q = (m_r - m_p)c^2. \] 
Substitute the values: 
\[ Q = (235.0439 - 234.8203) \times 931. \] 
Simplify: 
\[ Q = 0.2236 \times 931 = 208.1716 \, \text{MeV}. \] 
Answer: \(208 \, \text{MeV}\)

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