Question

A fires 5 shots to B's 3, but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, how many times has A killed?

• A. 15
• B. 30
• C. 40
• D. 35
• E. 25

Hint:

Standardize the number of shots fired by one person to find the equivalent number fired by the other using the given ratio.

Answer 1

The Correct Option is B

Step 1: Analyse options.
- B kills once in 2 shots, meaning B also misses once in 2 shots (1:1 ratio). - If B missed 27 times, B must have fired $27 \times 2 = 54$ shots. - The ratio of shots fired by A to B is 5:3. - Total shots fired by A = $\frac{5}{3} \times 54 = 90$ shots. - A kills once in 3 shots. - A's kills = $\frac{90}{3} = 30$.
Step 2: Conclusion.
A has killed 30 times. Final Answer: (b) 30