Men | Tunnel | Days | |
---|---|---|---|
Initial | 140 | 1.5 km | 60 |
Remaining | X | 4.5 km | 140 |
\(X = 140×\frac{4.5}{1.5}×\frac{60}{140} = 180\)
Additional men required = \(180-140 = 40\)
A contractor agreed to build a road in \(200\) days and had \(140\) persons to do work.
After \(60\) days, only \(\frac 14^{th}\) of the road could be build.
We know that,
\(\frac {M_1 × D_1 × T_1}{W_1}= \frac {M_2 × D_2 × T_2}{W_2}\)
Amount of work remaining \(= 1-\frac 14 = \frac 34\) unit of work.
Number of days in which the remaining work needs to be completed \(= 200 - 140 = 60\) days.
Let \(x \) persons be extra needed to finish the work.
\(\frac {140 × 60}{\frac 14}= \frac {(140 + x) × 140}{\frac 34}\)
\(4 × 60= \frac {(140 + x) × 4}{3}\)
\(140+x=180\)
\(x=180-140\)
\(x=40\)
So, the answer is \(40\).