Question:

A conducting loop in the shape of a right angled isosceles triangle of height $10\, cm$ is kept such that the $90^{\circ}$ vertex is very close to an infinity long conducting wire (see the figure). The wire is electrically insulated from the loop. The hypotenuse of the triangle is parallel to the wire. The current in the triangular loop is in counterclockwise direction and increased at a constant rate of $10 \,As ^{-1}$. Which of the following statement (s) is (are) true?

Updated On: Jan 18, 2023
  • There is a repulsive force between the wire and the loop,
  • If the loop is rotated at a constant angular speed about the wire, an additional emf of $\left(\frac{\mu_{0}}{\pi}\right)$ volt is induced in the wire
  • The magnitude of induced emf in the wire is $\left(\frac{\mu_{0}}{\pi}\right)$ volt
  • The induced current in the wire is in opposite direction to the current along the hypotenuse
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The Correct Option is C

Solution and Explanation

Here $\frac{ di }{ dt }=10 A / S$
for mutual inductance
$ d \phi=\frac{\mu_{0}}{2 \pi} \frac{ i }{ r }(2 r dr ) $
$\phi=\frac{\mu_{0}}{\pi} i \int\limits_{0}^{4} dr$
$\phi=\left(\frac{\mu_{0}}{\pi} d \right) i = Mi $
$ M =\frac{\mu_{0}}{\pi} d =0.1 \frac{\mu_{0}}{\pi}$
When current through loop increases then magnetic flux
$\phi= Mi $
$\varepsilon=\frac{d \phi}{ dt } $
$\varepsilon= M \frac{ di }{ dt }=\frac{\mu_{0}}{\pi} \times 10 \times 0.1$
$\varepsilon=\frac{\mu_{0}}{\pi}$
Force between loop and conductor is repulsive.
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Concepts Used:

Faradays Laws of Induction

There are two laws, given by Faraday which explain the phenomena of electromagnetic induction:

Faraday's First Law:

Whenever a conductor is placed in a varying magnetic field, an emf is induced. If the conductor circuit is closed, a current is induced, known as the induced current.

Faraday's Second Law:

The Emf induced inside a coil is equal to the rate of change of associated magnetic flux.

This law can be mathematically written as:

\(-N {\triangle \phi \over \triangle t}\)