Question:
A child is born with blood group AB. If the child is not an illegitimate one, the correct parental combination must be:
A child is born with blood group AB. If the child is not an illegitimate one, the correct parental combination must be:
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AB blood group: I\(^A\)I\(^B\).
Parents: A and B genotypes.
Both parents must contribute different alleles.
Parents: A and B genotypes.
Both parents must contribute different alleles.
Updated On: Aug 18, 2026
- Both the parents belong to blood group A
- One parent belongs to blood group O and other to AB
- Both the parents belong to blood group AB
- One parent belongs to blood group A and other to B
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
Blood group inheritance follows Mendelian genetics.
ABO blood groups have specific genotypes.
Step 2: Key Formula or Approach:
No specific formula.
Need to understand blood group inheritance.
Step 3: Detailed Explanation:
For a child to have blood group AB, the genotype must be I\(^A\)I\(^B\).
One parent must contribute I\(^A\) and the other I\(^B\).
Thus, one parent must have A (I\(^A\)I\(^-\)) and the other B (I\(^B\)I\(^-\)).
Option D is the correct combination.
Step 4: Final Answer:
One parent must be A and the other B.
Hence, the correct option is (D).
Blood group inheritance follows Mendelian genetics.
ABO blood groups have specific genotypes.
Step 2: Key Formula or Approach:
No specific formula.
Need to understand blood group inheritance.
Step 3: Detailed Explanation:
For a child to have blood group AB, the genotype must be I\(^A\)I\(^B\).
One parent must contribute I\(^A\) and the other I\(^B\).
Thus, one parent must have A (I\(^A\)I\(^-\)) and the other B (I\(^B\)I\(^-\)).
Option D is the correct combination.
Step 4: Final Answer:
One parent must be A and the other B.
Hence, the correct option is (D).
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