Question:

A body $ A $ thrown vertical upwards with a velocity v reaches a height of $ 200\, m $ . Another body $ B $ whose mass is twice that of $ A $ is thrown with a velocity $ 2v $ . Find the maximum height reached by $ B $ .

Updated On: May 15, 2024
  • $ 400\, m $
  • $ 800\, m $
  • $ 100\, m $
  • $ 200\, m $
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The Correct Option is B

Solution and Explanation

Maximum height of the particle thrown is independent of its mass and is given by
$H=\frac{v^{2}}{2\,g}$
For body A : $200=\frac{v^{2}}{2g} \dots(i)$
For body B : $H=\frac{(2v)^{2}}{2g}$
$=\frac{4 v^{2}}{2g}$
$=(4 \times 200)=800\,m$ (from (i))
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Concepts Used:

Physical World

The physical world includes the complications of the natural world around us. It is a type of analysis of the physical world around us to understand how it works. The fundamental forces that control nature are:

  • Gravitational Force is a universal force that exists as an outcome of mutual attraction between any two objects with respect to their masses.
  • Electromagnetic Force can be understood as the force that is present between the charged particles. The force is stated by Coulomb’s law.
  • Strong Nuclear Force is the force that ties the protons and neutrons in a nucleus. Of all the elemental forces in nature, a strong nuclear force is the strongest as its name suggests.
  • Weak Nuclear Force can only be noticed in some of the nuclear processes such as the beta decay of the nucleus.