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A blind man lives in an apartment containing 2 rooms. Each day before going to work he enters any one room randomly, picks up a bag and leaves home. One of the rooms contains 3 blue, 4 green and 5 red bags and the other contains 2 blue, 1 green and 3 red bags. What is the probability that he takes a green bag to his workplace?
A blind man lives in an apartment containing 2 rooms. Each day before going to work he enters any one room randomly, picks up a bag and leaves home. One of the rooms contains 3 blue, 4 green and 5 red bags and the other contains 2 blue, 1 green and 3 red bags. What is the probability that he takes a green bag to his workplace?
Updated On: Jul 26, 2024
- \(\frac{1}{4}\)
- \(\frac{1}{3}\)
- \(\frac{1}{2}\)
- \(\frac{2}{3}\)
- \(\frac{3}{4}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{1}{4}\)
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