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A bag has 5 blue balls and 15 red balls. Three balls are drawn at random from the bag simultaneously. Then the probability that none of the chosen balls is blue equals
A bag has 5 blue balls and 15 red balls. Three balls are drawn at random from the bag simultaneously. Then the probability that none of the chosen balls is blue equals
Updated On: Oct 1, 2024
- \(\frac{75}{152}\)
- \(\frac{91}{228}\)
- \(\frac{27}{64}\)
- \(\frac{273}{800}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac{91}{228}\)
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