Question:
A, B and C have some marbles. The ratio of the number of marbles with A to the number with B is 2:1. Also, the number of marbles with A to the number with C is 1:4. What is the approximate percentage of the total number of marbles that are with C?
A, B and C have some marbles. The ratio of the number of marbles with A to the number with B is 2:1. Also, the number of marbles with A to the number with C is 1:4. What is the approximate percentage of the total number of marbles that are with C?
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For ratio problems, express the quantities in terms of a common variable and then solve.
Updated On: Mar 24, 2026
- 25.00%
- 33.33%
- 72.72%
- 75.00%
- 80.00%
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The Correct Option is C
Solution and Explanation
Let the number of marbles with A be \( 2x \), the number with B be \( x \), and the number with C be \( 4x \) (since the ratio of A to B is 2:1 and the ratio of A to C is 1:4).
Step 1: Total number of marbles is: \[ 2x + x + 4x = 7x \] Step 2: The percentage of marbles with C is: \[ \frac{4x}{7x} \times 100 = \frac{4}{7} \times 100 \approx 57.14% \]
Step 1: Total number of marbles is: \[ 2x + x + 4x = 7x \] Step 2: The percentage of marbles with C is: \[ \frac{4x}{7x} \times 100 = \frac{4}{7} \times 100 \approx 57.14% \]
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