Let boys \(=B\), girls \(=G\). Then \(B+G=300\) and \(2.4B+2.8G=776\).
Multiply by 10: \(24B+28G=7760\Rightarrow 6B+7G=1940\).
Using \(B=300-G\): \(6(300-G)+7G=1940\Rightarrow 1800-G=1940\Rightarrow G=140\).
\[
\boxed{140}
\]
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