Question:
5 boys with allotted roll numbers and seat numbers are seated in such a way that no one sits on the allotted seat. The number of such seating arrangements is?
5 boys with allotted roll numbers and seat numbers are seated in such a way that no one sits on the allotted seat. The number of such seating arrangements is?
Updated On: Mar 28, 2026
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Solution and Explanation
The correct answer is 44
Number of seating arrangements
\(= 5! \left( 1- \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \frac{1}{4!} + \frac{1}{5!}\right)\)
\(= 5! \left(\frac{120-120+60-20+5-1}{120} \right)\)
\(= 44\)
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Concepts Used:
Permutations and Combinations
Permutation:
Permutation is the method or the act of arranging members of a set into an order or a sequence.
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Combination:
Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.
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- The combination is used for a group of data where the order of data does not matter.