Question:

40 men took a dip in a water tank 30 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 cu.m, then the approximate rise in the water level in the tank will be .

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Divide the total volume of water displaced by the base area of the tank.
  • 40 cm
  • 36 cm
  • 27 cm
  • 22 cm
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The Correct Option is C

Solution and Explanation

Step 1: Total volume of water displaced = number of men x volume per man = \(40 \times 4 = 160\) cu.m.
Step 2: Base area of tank = \(30 \times 20 = 600\) sq.m.
Step 3: Rise in water level = volume / area = \(160/600 = 0.267\) m.
Step 4: Converting to cm: \(0.267 \times 100 \approx 27\) cm.
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