Question:

$ 3a{{\int_{0}^{1}{\left( \frac{ax-1}{a-1} \right)}}^{2}}\,\,dx $ is equal to

Updated On: Jun 23, 2024
  • $ a-1+{{(a-1)}^{-2}} $
  • $ a+{{a}^{-2}} $
  • $ a-{{a}^{-2}} $
  • $ {{a}^{2}}+\frac{1}{{{a}^{2}}} $
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The Correct Option is A

Solution and Explanation

$ 3a\int_{0}^{1}{{{\left( \frac{ax-1}{a-1} \right)}^{2}}\,dx=\frac{3a}{{{(a-1)}^{2}}}}\left[ \frac{{{(ax-1)}^{3}}}{3}\times \frac{1}{a} \right]_{0}^{1} $
$ =\frac{1}{{{(a-1)}^{2}}}[{{(a-1)}^{3}}+1] $
$ =(a-1)+{{(a-1)}^{-2}} $
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Concepts Used:

Integrals of Some Particular Functions

There are many important integration formulas which are applied to integrate many other standard integrals. In this article, we will take a look at the integrals of these particular functions and see how they are used in several other standard integrals.

Integrals of Some Particular Functions:

  • ∫1/(x2 – a2) dx = (1/2a) log|(x – a)/(x + a)| + C
  • ∫1/(a2 – x2) dx = (1/2a) log|(a + x)/(a – x)| + C
  • ∫1/(x2 + a2) dx = (1/a) tan-1(x/a) + C
  • ∫1/√(x2 – a2) dx = log|x + √(x2 – a2)| + C
  • ∫1/√(a2 – x2) dx = sin-1(x/a) + C
  • ∫1/√(x2 + a2) dx = log|x + √(x2 + a2)| + C

These are tabulated below along with the meaning of each part.