Step 1: Understanding the Question:
This question is from the chapter "Real Numbers", specifically addressing the classification of numbers as prime or composite.
A prime number is a natural number greater than 1 that has exactly two distinct positive divisors: 1 and itself.
A composite number is a natural number greater than 1 that has more than two distinct positive divisors.
We need to analyze the properties of the given numerical expression $(3 \times 11 \times 13 + 3)$ and classify it accordingly.
Step 2: Key Formula or Approach:
To check whether a number of the form $a \cdot b \cdot c + d$ is prime or composite, we can factor out common terms.
By expressing the number as a product of two integers both greater than 1, we can prove it is composite without necessarily computing the entire large multiplication.
Let's find a common factor between the terms of the expression.
Step 3: Detailed Explanation:
• Write down the given expression:
\[ 3 \times 11 \times 13 + 3 \]
• Notice that there are two terms in this expression: the product $(3 \times 11 \times 13)$ and the number $3$.
Both terms share a common factor of $3$.
• Factor out $3$ from the expression:
\[ 3 \times (11 \times 13 + 1) \]
• Simplify the expression inside the parentheses:
\[ 11 \times 13 = 143 \]
Now, add 1 to this product:
\[ 143 + 1 = 144 \]
• Now, rewrite the original expression as a product:
\[ 3 \times 144 \]
• Compute the final value:
\[ 3 \times 144 = 432 \]
• Let us analyze the number $432$:
• Since $432 = 3 \times 144$, it has factors other than 1 and itself (such as 2, 3, 4, 6, etc.). Therefore, it is
not a prime number.
• Is it divisible by $13$? Let's divide $432$ by $13$:
$432 = 13 \times 33 + 3$. Since there is a remainder of 3, it is
not divisible by 13.
• Is it an odd number? No, the last digit is 2, so $432$ is an
even number.
• Since $432$ is greater than 1 and has multiple factors, it is a
composite number.
Step 4: Final Answer:
Therefore, the given number is a composite number, which matches Option (C).