Concept:
This problem uses the work-days relationship formula: \(\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}\), where \( M \) is the number of workers, \( D \) is the number of days, and \( W \) is the fraction of work completed.
Step 1: Analyze the initial work phase.
Given: \( M_1 = 160 \), \( D_1 = 40 \), \( W_1 = \frac{1}{5} \).
Step 2: Determine the requirements for the remaining work.
Remaining work (\( W_2 \)) = \( 1 - \frac{1}{5} = \frac{4}{5} \).
Remaining time (\( D_2 \)) = \( 120 - 40 = 80 \) days.
Step 3: Apply the formula to find the total workers needed (\( M_2 \)).
\[
\frac{160 \times 40}{1/5} = \frac{M_2 \times 80}{4/5}
\]
\[
160 \times 40 \times 5 = M_2 \times 80 \times \frac{5}{4}
\]
\[
32000 = M_2 \times 100 \implies M_2 = 320
\]
Step 4: Calculate additional workers.
\[
\text{Additional workers} = M_2 - M_1 = 320 - 160 = 160
\]
\centerline{{160}}