List of top Physics Questions on Gravitational Potential Energy asked in KEAM

If the magnitude of gravitational potential energy of an object of mass $200$ kg at a height of $3.6 \times 10^6$ m from the earth surface is $6 \times 10^6$ J then its value at a height of $5.6 \times 10^6$ m is (Radius of earth is $6.4 \times 10^6$ m)
When a satellite moves from the farthest stable orbit to the nearest stable orbit towards the earth, its gravitational potential energy
The ratio of the magnitudes of gravitational potential energy to that of kinetic energy of an earth satellite of mass $m$ revolving in any orbit is
If orbital radius of geostationary satellite decreases, gravitational potential energy
The gravitational potential energy of a body of mass m on the surface of earth of mass M and radius R is ________.
If \( K \) is the kinetic energy of a satellite at a height \( h \) from the surface of earth, then its total energy is
The ratio between the gravitational potential energies of 1 kg of mass on the surface of two planets having masses and radii in the ratio \(1 : 2\) and \(1 : 3\) respectively, is
What is the potential energy of an object of mass \( m \) placed on the surface of the Earth? (Mass of Earth = \( M \), radius of Earth = \( R \))
The orbital velocity of a satellite is $ V_0 $, at a height $ h = R $ (where $ R $ is the radius of the Earth) from the surface of the Earth. What is the relationship between $ V_0 $ and the escape velocity $ V_e $?
The gravitational potential energy of a system of two bodies each of mass $m$ and distance $r$ between them is (G = gravitational constant, g = acceleration due to gravity)
The dimensional formula of the gravitational constant is \( M^a L^b T^c \), the values of \( a \), \( b \), and \( c \) are respectively:
Gravitational potential energy associated with two point masses, each of 1 kg, separated by a distance of 1cm in Joule is (G= gravitational constant)
Consider a satellite moving in a circular orbit around Earth. If $K$ and $V$ denote its kinetic energy and potential energy respectively then (Choose the convention where $V = 0$ as $r \to \infty$)
A body of mass \(m\) is released from a height equal to the radius \(R\) of earth. The velocity with which it will strike earth’s surface is
If a body of mass \(m\) has to be taken from the surface of earth to a height \(h = R\), then the amount of energy required is (\(R\): radius of earth)
If a body of mass \(m\) has to be taken from the surface of earth to a height \(h = R\), then the amount of energy required is (\(R\): radius of earth)
If a body of mass \(m\) has to be taken from the surface of earth to a height \(h = R\), then the amount of energy required is (\(R\): radius of earth)
The change in potential energy when a body of mass $ m $ is raised to a height $ nR $ from earths surface is (R = radius of the earth)