List of top Physics Questions on Energy in simple harmonic motion asked in KEAM

When the displacement of a particle executing simple harmonic motion is half its amplitude, the ratio of its kinetic energy to potential energy is:
If the time period of a particle executing SHM is 8 s, then the time period of the potential energy of this particle is
A particle executes linear simple harmonic motion and its potential energy (P.E.), kinetic energy (K.E.), total energy (T.E.) are measured as functions of displacement \(x\) from the mean position at the origin. Then
A particle of 100 g mass is projected vertically up with a kinetic energy of 20 J. The maximum height reached by the particle is (\( g = 10 \) m/s\( ^2 \)) (neglecting air resistance).
Impending motion is opposed by:
The total energy of the particle executing simple harmonic motion of amplitude A is 100 J. At a distance of 0.707 A from the mean position, its kinetic energy is
The total energy of the particle executing simple harmonic motion of amplitude A is 100 J. At a distance of 0.707 A from the mean position, its kinetic energy is
The total energy of the particle executing simple harmonic motion of amplitude A is 100 J. At a distance of 0.707 A from the mean position, its kinetic energy is
A body oscillates with SHM according to the equation (in SI units), $x = 5 cos \left(2\pi t +\frac{\pi}{4}\right) .$ Its instantaneous displacement at $t = 1$ second is