List of top Physics Questions on Projectile motion asked in KEAM

The horizontal range of a projectile is maximum when the angle of projection is ____.
Which of the following is true in an SHM?
If maximum height and range are equal in projectile motion, then $ \tan \theta = ... $:
A cricmeter hits a ball with an initial velocity of 40 m/s. Calculate the maximum range.
A projectile is given an initial velocity of $(\hat{i} + \hat{j})$ m/s, where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical direction. The equation of its trajectory is $(g = 10 \, \text{m/s}^2)$.
A projectile is projected with a velocity of \( 20 \, {ms}^{-1} \) at an angle of 45° to the horizontal. After some time its velocity vector makes an angle of 30° to the horizontal. Its speed at this instant (in \( {ms}^{-1} \)) is:
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is
The relation between the time of flight of projectile $T_f$ and the time to reach the maximum height $t_m$ is
Two particles $ A $ and $ B $ are projected with same speed so that the ratio of their maximum heights reached is $ 3:1 $ . If the speed of $ A $ is doubled without altering other parameters, the ratio of the horizontal ranges attained by $ A $ and $ B $ is
The vertical component of velocity of a projectile at its maximum height ($u =$ velocity of projection, $\theta =$ angle of projection) is