List of top Physics Questions on Projectile motion asked in KEAM

A body is projected up with a velocity of $30 \text{ ms}^{-1}$ at an angle of $30^\circ$. The ratio of maximum height reached to the height reached in the first second is ($g = 10 \text{ms}^{-2}$)}
A particle projected with a velocity at an angle of \(30^\circ\) to the horizontal, travels a horizontal range R. If it is projected with the same velocity at \(60^\circ\) to the horizontal, its horizontal range will be
If a ball is thrown horizontally with a velocity of $10\text{ ms}^{-1}$ from the tower of height 45 m, then it strikes the ground at a distance of $(g=10\text{ ms}^{-2})$
The horizontal range of a projectile is maximum when the angle of projection is ____.
A cricketer hits a ball at $45^{\circ}$ with velocity $40\ \text{m s}^{-1}$ and it falls at $160\ \text{m}$. If he hits at the same angle with $50\ \text{m s}^{-1}$, the distance will be:
If \(\theta\) is the angle of projection of an object for which the horizontal range is equal to the maximum height attained, then the value of \(\tan \theta\) is
Which of the following is true in an SHM?
If maximum height and range are equal in projectile motion, then $ \tan \theta = ... $:
A cricmeter hits a ball with an initial velocity of 40 m/s. Calculate the maximum range.
A projectile is given an initial velocity of $(\hat{i} + \hat{j})$ m/s, where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical direction. The equation of its trajectory is $(g = 10 \, \text{m/s}^2)$.
A projectile is projected with a velocity of \( 20 \, {ms}^{-1} \) at an angle of 45° to the horizontal. After some time its velocity vector makes an angle of 30° to the horizontal. Its speed at this instant (in \( {ms}^{-1} \)) is:
Two projectiles \(P\) and \(Q\) thrown with velocities \(v\) and \(\dfrac{v}{2}\) respectively have the same range. If \(Q\) is thrown at an angle of \(15^\circ\) to the horizontal, \(P\) must be thrown at an angle of
Which of the following graphs represents the speed $v$ of a projectile as a function of time $t$
A ball falls from a table top with initial horizontal speed $V_0$. In the absence of air resistance, which of the following statement is correct
From the ground, a projectile is fired at an angle of $60^\circ$ to the horizontal with a speed of $20$ m/s. Take acceleration due to gravity as $10$ m/s$^2$. The horizontal range of the projectile is
A body is thrown up with a speed \( u \), at an angle of projection \( \theta \). If the speed of the projectile becomes \( \frac{u}{\sqrt{2}} \) on reaching the maximum height, the maximum vertical height attained by the projectile is
A cricket ball is hit at an angle of 30° to the horizontal with a kinetic energy E. Its kinetic energy when it reaches the highest point is
The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is
The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is
The vertical component of velocity of a projectile at its maximum height ($u$ – velocity of projection, $\theta$ – angle of projection) is
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is
The relation between the time of flight of projectile $T_f$ and the time to reach the maximum height $t_m$ is
Two particles $ A $ and $ B $ are projected with same speed so that the ratio of their maximum heights reached is $ 3:1 $ . If the speed of $ A $ is doubled without altering other parameters, the ratio of the horizontal ranges attained by $ A $ and $ B $ is
The vertical component of velocity of a projectile at its maximum height ($u =$ velocity of projection, $\theta =$ angle of projection) is