List of top Mathematics Questions on Area under Simple Curves asked in KEAM

A curve with equation $y = x^3 - 8x^2 + 16x$ meets the $x$-axis at the origin $O$ and at a point $A$. Then the area of the region, bounded by the curve and the straight-line segment $OA$, is
The area of the region bounded by \(y = \sqrt{x}, y = -x\), and \(x = 4\) (in square units) is
The area of the region bounded by the lines, $y = x + 2$, $x = 0$, $x = 1$ and $y = 0$ is
The area bounded by $y=x-1$, $1\le x\le 2$, $y=0$ (in sq.units) is
The area of the region bounded by \(\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1\) and the line segment joining (0,5) and (4,0) in the first quadrant is
Find the area between the line $ y = x - 1 $, $ y = 0 $, $ -2 \leq y \leq 2 $.
The area of the region in the first quadrant enclosed by the curves\( y=√x,y=-x+6 \)and the x-axis is 
The area enclosed between the curve $y = 11x - 24 - x^2$ and the line $y = x$ is
The area enclosed within the curve \( |x| + |y| = 1 \) is
The area of the region bounded by the curves \( y = |x - 2| \), \( x = 1 \), \( x = 3 \) and \( y = 0 \) is:
The area of the triangular region whose sides are \( y = 2x + 1 \), \( y = 3x + 1 \) and \( x = 4 \) is:
The area bounded by the curves \( y = -x^2 + 3 \) and \( y = 0 \) is:
The area of the region bounded by $y^2 = 16 - x^2, y = 0, x = 0$ in the first quadrant is (in square units):
The area bounded by the parabola $ {{y}^{2}}=8x $ and its latus rectum in sq unit is