>
KEAM
>
Mathematics
List of top Mathematics Questions on Parabola asked in KEAM
The vertex of the parabola $2y = -3x^2 + 48x - 200$, is
KEAM - 2026
KEAM
Mathematics
Parabola
The coordinates of the focus of the parabola given by the equation \(4y - x^2 + 4x - 12 = 0\) are
KEAM - 2026
KEAM
Mathematics
Parabola
If the focus and vertex of a parabola are at a distance of 3 units and 6 units, respectively, from the origin on the positive x-axis, then the equation of the parabola is
KEAM - 2026
KEAM
Mathematics
Parabola
The axis of a parabola is $x=0$. If the vertex is at a distance 3 from the origin above the x-axis, the vertex of the parabola is at ________.
KEAM - 2025
KEAM
Mathematics
Parabola
Find the vertex of the parabola \( 4y = x^2 - 6x + 17 \).
KEAM - 2025
KEAM
Mathematics
Parabola
Find the focus of the parabola \( x^2 - 4x + 8y + 4 = 0 \).
KEAM - 2025
KEAM
Mathematics
Parabola
If the focus of a parabola is \( (0, -3) \) and its directrix is \( y = 3 \), then its equation is:
KEAM - 2024
KEAM
Mathematics
Parabola
The coordinates of the vertex of the parabola \[ y = 2x^2 - 12x + 26 \] are
KEAM - 2024
KEAM
Mathematics
Parabola
Find the equation of the parabola with focus at \( (3,1) \) and vertex at \( (5,1) \).
KEAM - 2024
KEAM
Mathematics
Parabola
The length of the latus rectum of the parabola
\( y^2 = x \)
is:
KEAM - 2024
KEAM
Mathematics
Parabola
The set of points of the form(t^2+t+1,t^2-t+1),where t is a real number, represents a/an
KEAM - 2023
KEAM
Mathematics
Parabola
The area of the region in the first quadrant which is above the parabola
\(y = x^2\)
and enclosed by the circle
\(x^2 +y^2 = 2 \)
and the y-axis is
KEAM - 2023
KEAM
Mathematics
Parabola
The equation of the parabola with focus (3, 0) and directrix x + 3 = 0 is
KEAM - 2021
KEAM
Mathematics
Parabola
The focus of the parabola
$y^2 - 4y - x+3=0$
is
KEAM - 2018
KEAM
Mathematics
Parabola
The focus of the parabola
$( y + 1)^2 = -8(x +2)$
is
KEAM - 2018
KEAM
Mathematics
Parabola
The slope of the straight line joining the centre of the circle \( x^2 + y^2 - 8x + 2y = 0 \) and the vertex of the parabola \( y = x^2 - 4x + 10 \) is:
KEAM - 2014
KEAM
Mathematics
Parabola
The slope of the straight line joining the centre of the circle \( x^2 + y^2 - 8x + 2y = 0 \) and the vertex of the parabola \( y = x^2 - 4x + 10 \) is:
KEAM - 2014
KEAM
Mathematics
Parabola
The slope of the straight line joining the centre of the circle \( x^2 + y^2 - 8x + 2y = 0 \) and the vertex of the parabola \( y = x^2 - 4x + 10 \) is:
KEAM - 2014
KEAM
Mathematics
Parabola